Q13 of 97 Page 205

In the given figure, it is given that AD=BC and AC=BD.

Prove that ∠CAD=∠CBD and ∠ADC=∠BCD.


From the given figure,

In triangles DAC and CBD, we have:


AD = BC


AC = BD


DC = DC


So, by SSS congruence rule


∆ADC ≅ ∆BCD


∴ By Congruent parts of congruent triangles we have:


∠CAD = ∠CBD


∠ADC = ∠BCD


∠ACD = ∠BDC


Hence, proved


More from this chapter

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In an isosceles ∆ABC, AB=AC and the bisectors of ∠B and ∠C intersect each other at O. Also, O and A are joined.

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