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5. Congruence of Triangles and Inequalities in a Triangle
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Q14 of 97 Page 195

In the given figure, AE=DB, CB=EF And ∠ABC=∠FED. Then, which of the following is true?

From the given figure, we have

AE = DB


And, CB = EF


Now, AB = (AD – DB)


= (AD – AE)


DE = (AD – AE)


Now, in ∆ABC and ∆DEF we have:


AB = DE


CB = EF


∠ABC = ∠FED


∴ By SAS congruence criterion


∆ABC ≅ ∆DEF


Hence, option (A) is correct

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Questions · 97
5. Congruence of Triangles and Inequalities in a Triangle
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