Q15 of 97 Page 195

In the given figure, BE ⊥ CA and CF ⊥ BA such that BE=CF. Then, which of the following is true?

From the given figure, we have

BE is perpendicular to CA

Also, CF is perpendicular to BA

And, BE = CF

Now, in ∆ABE and ∆ACF we have:

BE = CF (Given)

∠BEA = ∠CFA = 90^o

∠A = ∠A (Common)

∴ By AAS congruence criterion

∆ABE ≅ ∆ACF

Hence, option (A) is correct

If the altitudes from two vertices of a triangle to the opposite sides are equal, then the triangle is

In the given figure, AE=DB, CB=EF And ∠ABC=∠FED. Then, which of the following is true?

In the given figure, D is the midpoint of BC, DE ⊥ AB and DF ⊥ AC such that DE=DF. Then, which of the following is true?

In ∆ABC and ∆DEF, it is given that AB=DE and BC=EF. In order that ∆ABC≅∆DEF, we must have