In an isosceles ∆ABC, AB=AC and the bisectors of ∠B and ∠C intersect each other at O. Also, O and A are joined.
Prove that: (i) OB=OC (ii) ∠OAB=∠OAC

From the given figure, we have:
(i) In ∆ABO and ∆ACO
AB = AC (Given)
AO = AO (Common)
∠ ABO = ∠ ACO
∴ By SAS congruence rule
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OB = OB (By CPCT)
(ii) As, By SAS congruence rule
∆ABO ≅ ∆ACO
∴ ∠ OAB = ∠ OAC (By Congruent parts of congruent triangles)
Hence, proved
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