Q10 of 97 Page 195

In the given figure, AB=AC and OB=OC. Then, ∠ABO: ∠ACO=?

It is given in the question that,

In ∆OAB and ∆OAC, we have


AB = AC


OB = OC


OA = OA (Common)


∴ By SSS congruence criterion



∴ ∠ABO = ∠ACO


So, ∠ABO: ∠ACO = 1: 1


Hence, option (A) is correct

More from this chapter

All 97 →
8

In the given figure, AB>AC. Then, which of the following is true?

 9

In the given figure, AB>AC. If BO and CO are the bisectors of ∠B and ∠C respectively, then

 11

In ∆ABC, IF ∠C>∠B, then

 12

O is any point in the interior of ∆ABC. Then, which of the following is true?