Q12 of 94 Page 228

The dimensions of a room are (10 mx8mx 3.3 m). How many men can be accommodated in this room if each man requires 3 m3 of space?

We know that,

Volume of a cuboid = Length × Breadth × Height


Therefore,


Volume of the room = 10 × 8 × 3.3


= 264 m3


Space required by 1 person = 3 m3


Therefore,


Total number of people that can be accommodated =


= 88


Hence, option B is correct

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