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5. Outside Delhi - 2012
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Q23 of 52 Page 1

If the points A(x, y), B(3, 6) and C(–3, 4) are collinear, show that x – 3y + 15 = 0.

Point A (x, y)


B (3, 6)


C (-3, 4) are collinear


Collinear means they lie on the same straight line and the Slope of AB = Slope of BC,




y - 6 = 1/3 (x - 3)
y - 6 = 1/3x -1
y - 5 - 1/3x = 0


Multiply by -3,


We get;
-3y + 15 + x = 0


By Re-arranging


We get;
x - 3y + 15 = 0 (proved)


More from this chapter

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22

Find the coordinates of a point P, which lies on the line segment joining the points A(–2, –2) and B(2, 4) such that AP = 3/7 AB.

22

Find the area of the quadrilateral ABCD whose vertices are A(–3, 1), B(–2, –4), C(4, –1) and D(3, 4).

24

All kings, queens and aces are removed from a pack of 52 cards. The remaining cards are well shuffled and then a card is drawn from it. Find the probability that the drawn card is

(i) a black face card.


(ii) a red card.

25

The numerator of a fraction is 3 less than its denominator. If 1 is added to the denominator, the fraction is decreased by 1/15. Find the fraction.

Questions · 52
5. Outside Delhi - 2012
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