How many three-digit numbers are divisible by 11?
To find: 110 + 121 + 132 + ….... + 990
Given,
a = 110
d = 121 – 110 = 11
an = 990
a+(n – 1)d = 990
Therefore,
110 + (n -1) ×11 = 990
(n -1)×11 = 990 – 110 = 880
(n – 1)881/11 = 80
n- 1 = 80
n = 80+1 = 81
As,
Sn = n/2(a1+an)
= 81/2(110+990)
= 81/2(1100) = 81×550 = 44550
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