Find the value of k for which the roots of the equation kx(3x – 4) + 4 = 0, are equal.
kx (3x - 4) + 4 = 0
3kx2 + 4kx + 4 = 0
a = 3k
b = -4k
c = 4
D = 0 (Since Roots are equal)
b2 – 4ac = 0
∴ (-4k)2 – 4(3k)(4) = 0
16 k2 – 48k = 0
16 k(k – 3) = 0
16 k = 0 or k – 3 = 0
k = 0 or k = 3
As coefficient of x2 can’t be zero so, Rejecting k = 0 and,
∴ k = 3
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