Find whether -150 is a term of the A.P. 17, 12, 12, 7, 2, ….?
To solve this question, we equate nth term of this A.P. as -150. If n is a natural number then it lies in the A.P. otherwise it doesn’t.
For the A.P. series given,
a=17,
d=12-17=-5
nth term of A.P. = a + (n-1)d
= 17 + (n-1)(-5)=-150
⇒ (n-1)(-5)=-150-17=-167
⇒ n-1=167/5
⇒ n= 172/5
Here we see that n is not a natural number,
∴ -150 is not a term of this A.P.
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