From the top of a 15 m high building, the angle of elevation of the top of a cable tower is 60o and the angle of depression of its foot is 30o. Determine the height of the tower.

Let AB be the building, with AB=15m
And CE be the cable tower.
And D be the point at exact same height of A, CD=AB=15m
In ΔADC,


AD=15√3m
In ΔADE,


DE=15 × 3=45m
∴ Height of cable tower, CE=CD + DE=15 + 45=60m
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