Q18 of 49 Page 1

Draw a triangle ABC in which AB = 5 cm, BC = 6 cm and. Then construct a triangle whose sides are times the corresponding sides of

Steps of Construction:


1.First, we draw a triangle ABC of given dimensions.


2.Draw a line segment BC of length 6cm.


3.From B, make an angle of 60° and draw a ray BX from B.



4. Now taking B as center and radius of 5cm(length of AB), draw an arc on the ray. The point is A.


5. Join AC.



6. Now we have to make a triangle which is 5/7 times of this triangle.


7. Draw a ray BZ making an acute angle with the line BC.Make 7 equal arcs starting from B then B1 and so on till B7.



8. Join B7C. Draw a line from B5 parallel to B7C cutting BC at C’.



9. Draw another line from C’ parallel to CA cutting AB at A’.



10. A’BC’is our required triangle.


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