Draw a triangle ABC with side BC = 7 cm, and . Then construct a triangle whose sides are times the corresponding sides of ∠ABC.

∠A + ∠B + ∠C=180° (Sum of angles of a triangle)

105° + 45° + ∠C=180°

∠C=30°

Steps of Construction:

1.Draw a line segment BC of length 7cm.

2. Make an angle of 45° from B and an angle of 30° from C. The point where the rays meet is point A.

3.Draw a ray BZ making an acute angle with the line BC.Make 5 equal arcs starting from B, then B1 and so on till B5.

4.Join B5C.

5.As we have to get the triangle 3/5 times of this triangle ABC.

6.From B3, draw a line parallel to B5C cutting BC at C’.

7.Draw another line from C’ parallel to AC cutting AB at A’.

8. A’BC’ is our required triangle.