Two poles of equal heights are standing opposite to each other on either side of the road, which is 100 m wide. From a point between them on the road, the angles of elevation of the top of the poles are 60 � and 30 � respectively. Find the height of the poles.

Let AB and DE be equal poles that are 100m apart and the height of the poles be y m.
Let the point C be the point on road, x m far from AB.
Now Distance of C from DE will be (100-x) m.
In Δ ABC,


………(1)
In Δ CED


y√3=100-x
Putting the value of x from eq(1)



4y=100√3

y=25(1.73)=43.25m
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.


