Q1 of 47 Page 1

In Fig.1, PQ and PR are two tangents to a circle with centre O. If QPR = 46°, then calculate QOR

Given, PQ and PR are two tangents to a circle with centre O and QPR = 46°.

Since, the radius drawn to these tangents will be perpendicular to the tangents,


OQ PQ and OR PR.


OQP = ORP = 90°


We know that the sum of angles in a quadrilateral is 360°.


OQP + QPR + ORP + QOR = 360°


90° + 46° + 90° + QOR = 360°


226° + QOR = 360°


QOR = 360° - 226°


QOR = 134°


Ans. QOR = 134°


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