Rahim tosses two different coins simultaneously. Find the probability of getting at least one tail.

When two coins are tossed simultaneously, the possible outcomes are (H, H), (H, T), (T, H), (T, T), which are all equally likely.

The outcomes favorable to the event E, ‘at least one tail’ = (T, T), (H, T) and (T, H).

So, the number of outcomes favorable to E = 3.

We know that the theoretical (classical) probability of an event E, written as P (E), is defined as P (E) = Number of outcomes favorable to E / Number of all possible outcomes of the experiment

∴ P (E) = 3/4

Ans. The probability that Rahim gets at least one tail is 3/4.