A farmer connects a pipe of internal diameter 20 cm from a canal into a cylindrical tank which is 10 m in diameter and 2 m deep. If the water flows through the pipe at the rate of 4 km per hour, in how much time will the tank be filled completely?
Diameter of cylindrical tank, D = 10m
Radius of cylindrical tank, R = 5m
Depth of cylindrical tank, H = 2m
Internal diameter of cylindrical pipe, d = 20 cm
We know that 1m = 100cm.
Internal radius of cylindrical pipe, r = 10cm = 1/10 m
We know that 1km = 1000m.
Rate of flow of water, v = 4 km/h = 4000 m/h
Let t be the time taken to fill the tank completely.
Water flowed through the pipe = Volume of the cylindrical tank
So, πr2v × t = πR2H
⇒ π(1/10)2 (4000)t = π(5)2(2)
⇒ t = 5/4
Converting into minutes,
⇒ t = 5(60)/4
⇒ t = 75 mins
Ans. The tank will be filled completely in 75 minutes.
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