Solve the equation 
for x.
Given equation, 
⇒ 
⇒ 
Cross multiplying, we get
⇒ 5x + 15 = (11 - x) (x + 1)
⇒ 5x + 15 = 11x – x2 + 11 – x
⇒ 5x + 15 – 11x + x2 – 11 + x = 0
⇒ x2 – 5x + 4 = 0
By factorization method,
⇒ x2 - x – 4x + 4 = 0
⇒ x (x - 1) – 4 ( x - 1) = 0
⇒ (x - 1) (x – 4) = 0
⇒ x - 1 = 0 (or) x - 4 = 0
⇒ x = 1 (or) x = 4
The solution of the given equation is x = 1, 4.
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