Two elements 'A' and 'B' belong to the 3rd period of Modern periodic table and are in group 2 and 13 respectively. Compare their following characteristics in tabular form:
(a) Number of electrons in their atoms
(b) Size of their atoms
(c) Their tendencies to lose electrons
(d) The formula of their oxides
(e) Their metallic character
(f) The formula of their chlorides
(a) Electronic configuration of A = 2, 8, 2
Electronic configuration of B = 2, 8, 3
(b) Along a period the atomic size of elements decreases. Thus element A has a higher size than B.
(c) Along a period due to increase in effective nuclear charge the tendency to loss electrons decreases, thus A has more metallic character.
(d) Valency of an O atom is -2. Hence formula is A2 O2
Valance electrons B atom is 3. Hence formula is B2O3
(e) Along a period the metallic character of elements decreases. A is thus more metallic.
(f) Valency of a Cl atom is -1.
Number of valance electrons in A=2 hence ACI2
Number of valance electrons in B=2 hence BCI3
Characteristics | A | B |
(a) No. of electrons in their atom | 4 or 12 or 20 | 5 or 13 or 13 |
(b) Size of their atoms | Bigger | Smaller |
(c) Their tendencies to lose electrons | More | Less |
(d) The formula of their oxides | AO or A2 O2 | B2O3 |
(e) Their metallic character | More metallic | Less Metallic |
(f) The formula of their chlorides | ACI2 | BCI3 |
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