Draw the graph of 2(x + 3) – 3 (y + 1) = 0. Read a few solutions from the graph and verify the same by actual substitution. In each case, find the points where the line meets the two axes.        

The given equation is 2(x + 3) – 3(y + 1) = 0
⇒ 3(y + 1) = 2(x + 3)
⇒ 3y + 3 = 2x + 6 ⇒ 3y = 2x + 6 – 3      | by transposition
⇒ 3y = 2x + 3 ⇒ y =                | Dividing both sides by 3
To draw the graph, we use the table of corresponding values of x and y.

x	0	3	6
y	1	3	5

  
We plot the points (0, 1), (3, 3) and (6, 5)on the graph paper. Then we join the points by a ruler to get the line which is the graph of the given equation.     
 
Few solutions from the graph are (-3, -1),    
For (-3, -1) L.H.S. = 2 (-3 + 3) – 3 (-1 + 1) = 0 = R.H.S.
∴The solution (-3, -1) is verified
For  L.H.S. = 2 - 3(0 + 1) = 3 – 3 = 0 = R.H.S
∴ The solution is verified
The points where the given line meets the x-axis and the y-axis and respectively  and (0, 1).