Find at least 3 solutions for the following linear equation in two variables: 2x + 3y = 4
2x+3y = 4
Take x = 1,
2 ൱+3y = 4
⇒ 3y = 4 - 2 = 2
∴ y =
Take x = 2,
2 × 2 + 3y = 4
⇒ 3y = 4 - 4 = 0
∴ y = 0
Take x = 3,
2 × 3+3y = 4
⇒ 3y = 4 - 6 = -2
⇒ y =
∴ The three solutions of the given equation are x = 1, y =
; x = 2, y = 0 and x = 3, y =
.
Take x = 1,
2 ൱+3y = 4
⇒ 3y = 4 - 2 = 2
∴ y =
Take x = 2,
2 × 2 + 3y = 4
⇒ 3y = 4 - 4 = 0
∴ y = 0
Take x = 3,
2 × 3+3y = 4
⇒ 3y = 4 - 6 = -2
⇒ y =
∴ The three solutions of the given equation are x = 1, y =
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