Find at least 3 solutions for the following linear equation in two variables: 2x-3y+7= 0
2x-3y+7 = 0
Take x = 1,
2൱ -3y + 7 = 0 ⇒ -3y = -7-2 = -9 ∴ y = 3
Take x = 2,
2 × 2 - 3y + 7 = 0 ⇒ -3y = -4-7
⇒ -3y = -11 ∴ y =
Take x = 3,
2 × 3 - 3y+7 = 0 ⇒ -3y = -7-6 = -13 Þ y =
∴ The three solutions of the given equation are x = 1, y = 3; x = 2, y =
and x = 3, y =
.
Take x = 1,
2൱ -3y + 7 = 0 ⇒ -3y = -7-2 = -9 ∴ y = 3
Take x = 2,
2 × 2 - 3y + 7 = 0 ⇒ -3y = -4-7
⇒ -3y = -11 ∴ y =
Take x = 3,
2 × 3 - 3y+7 = 0 ⇒ -3y = -7-6 = -13 Þ y =
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