Find four solutions for the following equation: 2x-3(y-2) = 1

2x-3(y-2) = 1
    
Take x = 1,
2൱-3(y-2) = 1   ⇒ 2-3y+6 = 1 ⇒ -3y = 1-8 = -7            ⇒ y =            ∴ y =
Take x = 2,
2൲ -3(y-2) = 1   ⇒ 4-3y+6 = 1        ⇒  -3y = 1-10
                = -9           ∴ y = = 3
     Take x = 3,
2൳ -3(y-2) = 1
Þ 6-3y+6 = 1        ⇒ -3y = 1-12
                 = -11           ∴ y = =   
                
     Take x = 4,
2× 4-3(y-2) = 1   ⇒ 8-3y+6 = 1          ⇒ 3y = 1-14
                = -13    ∴ y = = ∴ The four solutions of the given equation are x = 1, y = ; x = 2, y = 3, x = 3, y = and x = 4, y = .