Find four solutions for the following equation: 12x + 5y= 0

12x+5y = 0
    Take x = 1,
12൱ + 5y = 0
Þ 5y+12 = 0      ⇒ 5y = -12       ∴ y =
Take x = 2,
12൲ + 5y = 0 ⇒ 24+5y = 0     ⇒ 5y = -24       ∴ y =
    Take x = 3,
12൳ + 5y = 0
     36+5y = 0      ⇒ 5y = -36       ∴ y =
  Take x = 4,
12൴ + 5y = 0
   48+5y = 0       ⇒ 5y = -48        ⇒ y = ∴ The four solutions of the given equation are x = 1, y = ; x = 2, y = , x = 3, y = and x = 4, y = .