Find four solutions for the following equation: 5x-3y = 0

5x-3y = 0
Take x = 1,
5൱ - 3y = 0 ⇒ 5-3y = 0   ⇒ -3y = -5      ∴ y =
   Take x = 2,
5൲ - 3y = 0 ⇒ 10 - 3y = 0    ⇒ -3y = -10       ⇒ y =
         y =
Take x = 3,
5൳ - 3y = 0 ⇒ 15-3y = 0     ⇒ 3y = 15       \\ y = 5
Take x = 4,
5൴ -3y = 0 ⇒ 20-3y = 0    ⇒ -3y = -20       ⇒ y = ∴ The four solutions of the given equation are x = 1, y = ; x = 2, y = , x = 3, y = 5 and x = 4, y = .