Find four solutions for the following equation: 2(x-1)+3y = 4

2(x-1)+3y = 4
    Take x = 1,
2(1-1)+3y = 4   ⇒ 0+3y = 4      ⇒ 3y = 4        ∴ y =
    Take x = 2,
2(2-1)+3y = 4   ⇒ 2+3y = 4      ⇒ 3y = 4-2
             = 2        ∴ y =
    Take x = 3,
2(3-1)+3y = 4
  ⇒ 4+3y = 4       ⇒ 3y = 4-4
               = 0      ∴  y = 0
    Take x = 4,
2(4-1)+3y = 4    ⇒ 6+3y = 4        Þ 3y = 4-6
             = -2         ⇒ y = ∴ The four solutions of the given equation are x = 1, y = ; x = 2, y = , x = 3, y = 0 and x = 4, y = .