Prove tan 2φ+ cot 2φ+ 2= sec 2φcosec 2φ.
Consider the left hand side:
= tan 2 φ + cot 2 φ + 2
= sec 2 φ - 1 + cosec 2 φ - 1 + 2
[Using Identity 1 + cot 2 φ = cosec 2 φ and 1 + tan 2 φ = sec 2 φ]
= sec 2 φ + cosec 2 φ
= sec 2 φ cosec 2 φ
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