Prove that (1 + cot θ - cosec θ) ( 1 + tan θ + sec θ)=2
Proof:
Taking LHS
(1 + cot θ - cosec θ) (1 + tan θ + sec θ)
Change all the trigonometric ratios into sin and cos terms.
We know,
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[∵ (a – b) (a + b) = a2 – b2]
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[∵sin2θ + cos2θ = 1]
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= 2
= RHS
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