Q18 of 58 Page 8


Evaluate, sec 210 o– cot 280 o+ .


L.H.S. = sec 2 10 o – cot 2 80 o +

= sec 2 (90° - 80°) – cot 2 80° +

= cosec 2 80° - cot 2 80° + (using that sin (90° - θ) = cos θ

and cos (90° - θ) = sin θ)

= 1 + (1/1)

(1 + cot 2 θ = cosec 2 θ and sin 2 θ + cos 2 θ = 1)

= 1 + 1

= 2

= R.H.S.

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