If cosec A= 2, find the value of

As cosec = Hypotenuse/perpendicular

⇒ AC = 2 , BC = 1

In right angled ΔABC by Pythagoras theorem,

AC² = AB² + BC²
(2)² = 1² + BC²
BC² = 4 – 1

= 3

BC = √3 k

As tan θ = perpendicular/base

Sin θ = perpendicular/hypotenuse

cos θ = base/hypotenuse
tan A = (1/√3)
sin A = (1/2)
cos A = (√3/2)