Find a point on the x-axis, which is equidistant from the points(7, 6) and (3,4).

Question

Philoid · Accepted Answer

Let the point on x-axis be P(x, 0)

Let A be (7, 6) and B be (3, 4)

Now PA =

PA2 = (x – 7)2 + 36

and PB =

PB2 = (x – 3)2 + 16

Given PA = PB

or PA2 = PB2

or (x – 7)2 + 36 = (x – 3)2 + 16

or x2 – 14x + 49 + 36 = x2 + 9 – 6x + 16

or -14x + 6x = 25 – 85

or -8x = -60

or 8x = 60

or 2x = 15 ⇒ x =

Hence the required point is