Q24 of 51 Page 10

Find the equation of the line passing through (-3,5) and perpendicular to the line through the points (2,5) and (-3,6).


Slope of line through (2,5) and (-3,6) is =

Slope of the perpendicular is 5

Hence equation of line through (-3,5) with slope 5 is

(y-5) = 5(x+3)

i.e. 5x – y + 20 = 0

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