Q47 of 51 Page 10

Find the equation of the right bisector of the line segment joining the points (3,4) and (-1,2).


Slope of the line joining the points (3, 4) and (-1, 2)

=

Therefore the slope of the perpendicular bisector is = -2

Midpoint of the line joining the points (3, 4) and (-1, 2)

()

= (1, 3)

The equation of the right bisector is

y - 3 = -2(x - 1)

y - 3 = -2x + 2

y + 2x = 5

More from this chapter

All 51 →
45
Prove that the line through the point (x1,y1) and parallel to the line Ax+By+C=0 is A(x-x1)+b(y-y1) = 0

46
Two lines passing through the point (2,3) intersect each other at an angle of 60° . If slope of one line is 2, find the equation of the other line.

48
(-1,3) to the line 3x-4y-16=0

49
The perpendicular from the origin to the line y = mx+c meets it at the point (-1,2). Find the values of m and c.