Q42 of 51 Page 10

Find the equation of the line perpendicular to the line x-7y+5=0 and having x -intercept 3.


x-7y+5=0

Any line perpendicular to x-7y+5 = 0 is 7x+y+k=0

Now (3,0) lies on it.

So, 7 x 3+0+k=0 or k = -21

Thus required equation is 7x+y-21=0 or 7x+y = 21(Required equation)

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