Attempt any two of the following subquestions:
If the cost of bananas is increased by 10 per dozen, one can get 3 dozen less for 600. Find the original cost of one dozen of bananas.
Let the original cost of dozen of bananas = x
Original number of dozens bought for 600 = 600/x
Now cost increases by 10,
New cost = x + 10
Now number of dozens bought = 600/(x + 10)
Given that,

⇒ 
⇒ 
⇒ 2000 = x(x + 10)
⇒x2 + 10x - 2000 = 0
⇒ x2 + 50x - 40x - 2000 = 0
⇒ x(x + 50) - 40(x + 50) = 0
⇒ (x - 40)(x + 50) = 0
⇒ x = 40 and x = - 50(rejected)
∴ Original cost of one dozen of bananas = 40.
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