Q2 of 27 Page 218

Find the area enclosed by each of the following figures


Area of square ABCF, Ar(ABCF) = (side)2


⇒ Ar(ABCF) = 182 = 324 sq.cm


Given Height of trapezium EDCF, h = 8 cm


As we know that,





⇒ Ar(EDCF) = 100 sq.cm


Area of given figure, Req. area = Ar(EDCF) + Ar(ABCF)


⇒ Req. area = 100 + 324 = 424 sq.cm


∴ Area of given figure is 424 sq. cm


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