Q5 of 27 Page 218

Find the area of each of the following fields. All dimensions are in metres.

As we know that,


And we have 3 triangles here, namely, Δ EFH, Δ AJG, Δ AKB


Therefore,




⇒ Ar(Δ EFH) = 400 sq. m


Similarly,




⇒ Ar(Δ AKB) = 750 sq.m


And,




⇒ Ar(Δ AJG) = 1400 sq. m


Also, there are three trapeziums, namely, EICD, ICBK and FHJG




⇒ Ar(EICD) = 3600 sq.m


Also,



⇒ Ar(ICBK) = 2100 sq.m


And,



⇒ Ar(FHJG) = 2400 sq.m


Now, the area of the given figure is equal to the sum of the individual areas of triangles and trapeziums.


⇒ Req. area = Ar(Δ EFH) + Ar(Δ AKB) + Ar(Δ AJG) + Ar(EICD) + Ar(ICBK) + Ar(FHJG)


⇒ Req. area = 400 + 750 + 1400 + 3600 + 2100 + 2400


⇒ Req. area = 10650 sq.m


∴ the area of the given figure is 10650 sq.m


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