The floor of a building consists of around 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of flooring if each tile costs rupees 20 per m2.
The diagonals of the rhombus given are 45 cm and 30 cm.
As we know that,
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⇒ Area of one tile = 675 sq.cm
Total area of floor = (area of one tile) × (Total number of tiles)
⇒ Area of floor = 675 × 3000 = 2025000 sq.cm = 202.5 sq.m
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⇒ Cost of flooring = 202.5 × 20
⇒ Cost = Rs. 4050
∴ Total cost of flooring is Rs. 4050
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