Q2 of 27 Page 218

Find the area enclosed by each of the following figures


Area of rectangle ABCD, Ar(ABCD) = BC × CD


⇒ Ar(ABCD) = 20 × 15 = 300 sq.cm


Given height of trapezium, h = 8 cm


Sum of parallel sides of trapezium = EF + AD


⇒ 6 + 15 = 21 cm




⇒ Ar(EFAD) = 84 sq.cm


Now, required area = Ar(EFAD) + Ar(ABCD)


⇒ 84 + 300


⇒ 384 sq.cm


∴ Area of given figure is 384 sq.cm


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