Find the sum of the following APs:
0.6, 1.7,2.8, ….., to 100 terms.
In the above series
First term (a) = 0.6
Common different (d) = n2 – n1 = 1.7 - 0.6 = 1.1
No. Of terms (n) = 100
The sum of the series is given by Sn = 
[2a + (n-1) d]
= 
[2×(0.6) + (100-1)1.1]
= 5505
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