In an AP :
given a = 7, an = 35 find d and s13
d is the common difference
a is the first term = 7
a13 = 35
a13 = a + (13-1)d
35 = 7 + (12)(d)
28 = 12 d
d = ![]()
The sum of the series is Sn =
[2a + (n-1) d]
S13 =
[2×7 + (13-1)
]
=
[42]
= 273
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