Q5 of 105 Page 155

Find the 12^th term of a GP. Whose 8^th term is 192 and the common ratio is 2.

Given,

common ratio (r) is 2.

8^th term is 192

⇒ ar^8-1 = 192

a×2⁷ = 192

a = =

12^th term of a GP = ar^12-1 = ar¹¹

= ×2¹¹ = 3072.

Which term of the GP.

√3, 3, 3√3…… is 729?

Which term of the GP.

, ,,….is ?

The 4^th term of a geometric progression is and the seventh term is Find the geometric series.

If the geometric progressions 162, 54, 18 …. and have their nth term equal. Find the value of n.

Questions · 105

6. Progressions

1 1 1 1 2 2 2 2 2 3 3 3 3 4 4 4 4 4 4 4 4 4 4 4 4 4 1 2 2 3 3 3 3 3 4 5 5 6 7 8 9 10 11 12 13 14 15 16 17 1 1 1 1 2 2 2 3 3 3 3 3 3 3 4 5 6 7 7 8 9 10 11 12 13 14 1 1 1 2 2 2 2 3 3 3 3 3 3 3 3 3 4 1 1 1 1 2 3 3 4 4 4 5 6 7

Find the 12th term of a GP. Whose 8th term is 192 and the common ratio is 2.