Q4 of 105 Page 155

Which term of the GP.
√3, 3, 3√3…… is 729?

First term (a) = √3

Common ratio (r)

n^th term in the GP (a_n) = ar^n-1

729 = √3×(√3)^n-1

3⁶ = √3ⁿ

Equating powers on both sides

= 6 ⇒ n = 12.

Find the indicated term of each geometric Progression

a₁ = -12, r = find a₆

Which term of the GP.

2, 8, 32, ……. is 512?

Which term of the GP.

, ,,….is ?

Find the 12^th term of a GP. Whose 8^th term is 192 and the common ratio is 2.

Questions · 105

6. Progressions

1 1 1 1 2 2 2 2 2 3 3 3 3 4 4 4 4 4 4 4 4 4 4 4 4 4 1 2 2 3 3 3 3 3 4 5 5 6 7 8 9 10 11 12 13 14 15 16 17 1 1 1 1 2 2 2 3 3 3 3 3 3 3 4 5 6 7 7 8 9 10 11 12 13 14 1 1 1 2 2 2 2 3 3 3 3 3 3 3 3 3 4 1 1 1 1 2 3 3 4 4 4 5 6 7

Which term of the GP.√3, 3, 3√3…… is 729?