Q10 of 49 Page 167

Find the point on the x-axis which is equidistant from (2, -5) and (-2, 9).

Let P(x,0) be the point

A(2,-5) and B(-2,9)


⇒ PA =


⇒ PB =


PA = PB


PA2 = PB2


(x-2)2 + (-5)2 = (x + 2)2 + 92


x2-4x + 4 + 25 = x2 + 4x + 4 + 81


8x = -56


X = 7


Point is (-7,0)


More from this chapter

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Name the type of quadrilateral formed, if any, by the following points, and give reasons for your answer.

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