Q2 of 49 Page 184

Find the value of ‘K’ for which the points are collinear.

(K, K) (2, 3) and (4, -1).

For points to be collinear area of ΔABC = 0

Area ΔABC =


=


=


=


=


⇒ K2 -11k-12 = 0


⇒ K(k-12) + (k-12) = 0


⇒ (K-12)(k + 1) = 0


⇒ K = 12 or k = -1


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