Find the area of the triangle formed by joining the mid-points of the sides of the triangle whose vertices are (0, -1), (2, 1) and (0, 3). Find the ratio of this area of the area of the given triangle.
1 sq. unit; 1 : 4
⇒ Let A(0,-1),B(2,1),C(0,3)
So midpoints of AB and BC and CD
⇒ Midpoint formula
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⇒ For AB = ![]()
AB = ![]()
AB = ![]()
⇒ For BC
BC = ![]()
BC = ![]()
BC = ![]()
⇒ For AC
AC = ![]()
AC = ![]()
AC = ![]()
(1,0)(1,2)(0,1)
Area ΔXYZ = ![]()
= ![]()
= ![]()
= ![]()
= 1 sq cm
⇒ Let A(0,-1),B(2,1),C(0,3)
⇒ Area ΔABC = ![]()
= ![]()
= ![]()
= ![]()
= 4 sq cm
∴ Ratio of Area of triangles is 1:4
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