Q15 of 49 Page 167

Find a relation between x and y such that the point (x, y) is equidistant from the points (-2, 8) and (-3, -5)

Let P(x,y) be the point

A(-2,8) and B(-3,-5)


⇒ PA =


⇒ PB =


PA = PB


PA2 = PB2


(x + 2)2 + (8-y)2 = (x + 3)2 + (y + 5)2


x2 + 4x + 4 + 64 -16y + y2 = x2 + 6x + 9 + y2 + 10y + 25


-2x-26y = -34


⇒ X + 13y = 17


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