Q2 of 49 Page 184

Find the value of ‘K’ for which the points are collinear.

(7, -2) (5, 1) (3, K)

For points to be collinear area of ΔABC = 0

Area ΔABC =


=


=


=


=


∴ 8-k = 0


K = 2


More from this chapter

All 49 →
1

Find the area of the triangle whose vertices are

(-5, -1), (3, -5), (5, 2)

 1

Find the area of the triangle whose vertices are

(0, 0) (3, 0) and (0, 2)

 2

Find the value of ‘K’ for which the points are collinear.

(8, 1), (k, -4), (2, -5)

 2

Find the value of ‘K’ for which the points are collinear.

(K, K) (2, 3) and (4, -1).