Q2 of 49 Page 184

Find the value of ‘K’ for which the points are collinear.

(8, 1), (k, -4), (2, -5)

For points to be collinear area of ΔABC = 0

Area ΔABC =


=


=


=


18-6k = 0


K = 3


More from this chapter

All 49 →
1

Find the area of the triangle whose vertices are

(0, 0) (3, 0) and (0, 2)

 2

Find the value of ‘K’ for which the points are collinear.

(7, -2) (5, 1) (3, K)

 2

Find the value of ‘K’ for which the points are collinear.

(K, K) (2, 3) and (4, -1).

 3

Find the area of the triangle formed by joining the mid-points of the sides of the triangle whose vertices are (0, -1), (2, 1) and (0, 3). Find the ratio of this area of the area of the given triangle.