Q4 of 49 Page 184

Find the area of the quadrilateral whose vertices, taken in order, are (-4, -2), (-3, -5), (3, -2) and (2, 3)

28 sq. units

⇒ Let A = (-4, -2), B = (-3, -5), C = (3, -2) and D = (2, 3)


We draw Line BD and divide the quadrilateral into 2 triangles


ΔABD and ΔBDC


Area of both triangles


⇒ Area ΔBDC =


=


=


=


=


=


= 16.5 units


A = (-4, -2), B = (-3, -5), D = (2, 3)


Area ΔABD =


=


=


=


=


= 11.5 units


⇒ Total area of quadrilateral = Sum of Area of triangles


= ΔBCD + ΔABD


= 16.5 + 11.5 units


= 28 sq units.


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